Delegates from 5 different schools are coming to Srimati sulochanadevi singhania school. The number of delegates from Kendriya vidyalaya is 42, 60 from Poddars', 210 from Hiranandani, 90 from Jamnalal and 84 from Lodha. They are being put up at Satkar Residency Hotel. What is the minimum number of rooms that would be required to accommodate so that each room has the same number of occupants and occupants are all from the same school?
Answer:
42 = 6 x 7
60 = 6 x 10
210 = 6 x 35
90 = 6 x 15
84 = 6 x 14
So, each room will have 6 delegates
total number of rooms = 7 + 10 + 35 + 15 + 14 = 81
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