A tank is filled in 10 hours by three pipes A, B and C. The pipe C is twice as fast as B and B is twice as fast as A. How much time will pipe A alone take to fill the tank?
Answer:
Let A fill in x hours.
So, B fills in x/2 hours
and C fills in x/4 hours
now, (1/x + 2/x + 4/x) = 1/10
therefore, x = 70 hours.
Answer:
Let A fill in x hours.
So, B fills in x/2 hours
and C fills in x/4 hours
now, (1/x + 2/x + 4/x) = 1/10
therefore, x = 70 hours.
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