JMO indicies

(6561)^(1/2) + (6561)^(1/4) + (6561)^(1/8) = .......................

JMO STD V and STD VI

Answer:

6561 = 3 x 3 x 3...... 8 terms

so, (6561)^(1/2) = (3)^(8(1/2)  

= (3)⁽⁴⁾

^{= 81}

(6561)^(1/4) 

= (3)^(8(1/4)  

= (3)⁽²⁾  

^{= 9}

(6561)^(1/8) 

= (3)^(8(1/8) 

= (3)⁽¹⁾ 

^{= 3}

^{S0, the value of the expression is 81 + 9 + 3 = 93}