A garrison had provisions for a certain
number of days. After 10 days, 1/5 of the men desert and it is found that the
provisions will now last just as long as before. How long was that?
a)
50 days b) 30 days c) 40 days d) 60 days
Answer:
Let “x” be the number of days the
provisions would last for the garrison of “y” men
We can re phrase the question
now.
“ there is provision for y men
for ( x – 10) days, and there is provision for ( y – y/5 = 4y/5) men for x
number of days”
So, x = (x – 10) * {y/(4y/5)}
Or, x = (5/4)( x – 10)
Or, 4x = 5x – 50
Or, x = 50 days. answer is a.
If 40 men can make 30 boxes in 20 days,
How many more men are needed to make 60 boxes in 25 days?
a)
28 b)
24 c) 22 d) 26
Answer:
40 x (60/30) x (20/25) =
64 men
So, extra men = 64 – 40 = 24. Answer is b.
Note: for making more number of boxes you will need more
number of men. So fraction must be more than 1............... (60/ 30)
In more number of days you will need less number of men.
So, the fraction should be less than 1............................(20/25)
In a camp, food was sufficient for 2000
people for 54 days. After 15 days, more people came and the food last only for
20 more days. How many people came?
a)
1900 b)
1800 c) 1940 d) 2000
Answer:
We will re-phrase the question
There is food for 2000 people for (54 – 15 = 39) days. Food lasted
for 20 days. So, how many people where there.
= 2000 x (39/20) = 3900
So, extra people who joined was = 3900 – 2000 = 1900
answer is a
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