numbers

Where X = 100²⁰⁰⁶ + 9x100²⁰⁰² – 2

Find the sum of digits of X

=10⁴⁰¹² + 9.10⁴⁰⁰⁴ – 2

=10⁴⁰⁰⁴(100000009) -2

=100000009000.........................0 -2

           

                         4004 times

=100000008999............................98

                         4004 times

= 1 + 8 + 9 x 4003 + 8

=17 + 36027

= 36043