This blog makes available plenty of questions for practice, for the Mathematics competitive exams. We also try to bring to students interesting ways of approaching the questions.
If you need any assistance in questions from IPM, MTSE, SCHOLARSHIP, OLYMPIAD, CBSE , ICSE or Board test papers, you may write to us.
Wednesday, September 11, 2013
miscellaneous equations,
Solve:ax3 = by3 = cz3,
And, (1/x) + (1/y) + (1/z) = (1/d)
Show that ax2 + by2
+ cz2 = d2 (aâ…“ + bâ…“ + câ…“)3
No comments:
Post a Comment