Two numbers are formed by the same two digits, and if the smaller number is divided by the greater the quotient is 4/7, and if the smaller is subtracted from the greater the remainder is 27. Find the number.
Answer:
Let the two numbers be x and y.
Condition 1
(10x + y)/(10y + x) = 4/7
or, 7(10x + y) = 4(10y +x)
or, 70x + 7y = 40y + 4x
or, 66x = 33y
or, 2x = y ---------------(1)
Condition 2
(10y + x) -(10x + y) = 27
or, 9y - 9x = 27
or, y - x = 3 -----------(2)
Substituting (1) in (2), we get
2x - x = 3
or, x = 3
and y = 6
The two numbers are 36 and 63.
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Answer:
Let the two numbers be x and y.
Condition 1
(10x + y)/(10y + x) = 4/7
or, 7(10x + y) = 4(10y +x)
or, 70x + 7y = 40y + 4x
or, 66x = 33y
or, 2x = y ---------------(1)
Condition 2
(10y + x) -(10x + y) = 27
or, 9y - 9x = 27
or, y - x = 3 -----------(2)
Substituting (1) in (2), we get
2x - x = 3
or, x = 3
and y = 6
The two numbers are 36 and 63.
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