2/3 of the committee members are females. 1/4 of the male members are married. If there are 9 unmarried male members in the committee, then how many members are there in the committee?
Answer:
let the number of members be y
so, females = 2y/3
males = y - 2y/3 = y/3
number of married males = (1/4) x y/3 = y/12
unmarried males = y/3 - y/12 = 3y/12 = y/4
But unmarried males = 9 given
therefore, y/4 = 9
or, y = 36.
So, number of members in the committee is 36.
Answer:
let the number of members be y
so, females = 2y/3
males = y - 2y/3 = y/3
number of married males = (1/4) x y/3 = y/12
unmarried males = y/3 - y/12 = 3y/12 = y/4
But unmarried males = 9 given
therefore, y/4 = 9
or, y = 36.
So, number of members in the committee is 36.
No comments:
Post a Comment