Use
the Remainder Theorem to factorize the following expression:
2x3 +x2 - 13x + 6. (ICSE 2010)
Answer:
Substitute 1,2 and 3 to check if F(x) = 2x3 +x2 - 13x + 6 = 0
We find that for x = 2, F(2) = 0
So, (x -2) is a factor.
The other factor is of the form ax2 + bx + c, because F(x) is a
trinomial.
Therefore (x-2)( ax2 + bx + c) = 2x3 +x2 - 13x + 6
Or, ax3 + (b -2a)x2 – (c -2b)x – 2c =2x3 +x2 - 13x + 6
Comparing the coefficients of the individual powers of x on LHS and RHS,
We have a = 2,
(b – 2a) = 1
Or, b = 5
And -2c = 6
Or, c = -3
So, ax2 + bx + c = 2x2 + 5x – 3 = 2x2 + 6x – x – 3= 2x(x + 3) – 1(x + 3) =
(2x – 1)(x + 3)
Therefore, 2x3 +x2 - 13x + 6 = (x-2)(2x – 1)(x +
3) answer
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