mixtures, STD V

A, B and C have $ 507 between them. B and C together have $ 345 and C and A together have $ 305. How much does C have?

Answer:

A+B+C =507--------(1)

B+C = 345----------(2)

A+C = 305----------(3)

Adding (2) and (3), we get A+2B+C = 345 + 305------(4)

Substituting (1) in (4), we get

507 + B = 650

Or, B = 143

Therefore, C = 345 – 143 = 202

A Sum of money is divided into A, B and C. C gets twice as much as A, A and B together get $70, and B and C together get $90. How much does each person get?

Answer:

2A = C -------(1)

A + B = 70------(2)

B +C = 90-------(3)

(2) – (3)

A – C = -20,-----(4)

Substituting (1) in (4), we get

A – 2A = -20

Or, A = 20, therefore B = 50 and C = 40