In the addition Problem at the right, find the sum of the digits represented by B and C. Different letters represent different digits. Each time a same letter appears, it represents the same digit.
2 B A
+ C 6 D
8 A D
Answer:
Since A + D = D , So, A = 0
since B + 6 = 0 , B must be 4. There is carry 1 to the next place.
2 + C + 1 (carry) = 8
or, C = 5
So, B + C = 4 + 5 = 9
2 B A
+ C 6 D
8 A D
Answer:
Since A + D = D , So, A = 0
since B + 6 = 0 , B must be 4. There is carry 1 to the next place.
2 + C + 1 (carry) = 8
or, C = 5
So, B + C = 4 + 5 = 9
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