Interior angles of triangle (STD VI, STD. VII)

Geometry, triangle (STD. VI / STD. VII)

In a triangle, the interior angles are in the ratio, thus:

2A = 3B = 6C.

Find the angles of the triangle.

Answer

Let, 2A = 3B = 6C = K, say

So, A = K/2, B = K/3 and C = K/6

Since interior angles of a triangle is 180^o.

So , K/2 + K/3 + K/6 =180^o

This implies, K = 180^o   

Therefore, A= K/2 = 90^o, B = K/3 = 60^o and C = K/6 = 30^o