Showing posts with label STD VI. Show all posts
Showing posts with label STD VI. Show all posts

Tuesday, December 30, 2014

Sunday, December 21, 2014

HCF and LCM

Three numbers are in the ratio of 3:6:9 and their LCM is 2700. What is the HCF?

Tuesday, December 16, 2014

ratio and proportion

The ratio of marks obtained by Nanu and Bhanu is 6:5. If the combined average of their percentage is 68.75 and their sum of the marks is 275, find the total marks for which exam was conducted. 

ratio and proportion, ipm, mtse

A house has dogs, cats and parrot in the ratio of 3:7:5. If the number of cats was more than the number of dogs by a multiple of both 9 and 7 then what is the minimum of pets in the house possible?

Monday, November 24, 2014

divisibility, numbers

Let n be the total number of different 5 digit numbers that are divisible by 4. The digits comprise of 1, 2, 3, 4, 5 and 6. No digit is repeated in a number. What is the value of n?


divisibility

If n is a positive integer and (n + 1)(n + 3) is odd, then show that (n + 2)(n + 4) must be a multiple of 8.


Wednesday, October 22, 2014

JMO questions STD V / STD VI

1.       You are given that 47658 x 39876 = 1900410408. Without directly multiplying, use the given information to solve the following question:
52.342 x 0.60124
2.       Find the value of 19999 x 299999 using the information 19999 = 20000 – 1 and 299999 = 300000 – 1.
3.       Consider the number 12345.....11121314........566. Find the 500th digit.
                                                                                                                                  
Find 4 fractions which lie between 2/3 and 3/4  such that they divide the fractions in 5 equal parts.                           

Saturday, September 27, 2014

Average

There are three numbers, the average of first two numbers is 2 and the average of the last two numbers is 3, and the average of the first and the last numbers is 4. What is the average of three numbers?


Wednesday, September 3, 2014

JMO - numbers



If you have an operator (!) such that:
1! = 1
2! = 2 x 1
3! = 3 x 2 x 1
And it is also given that 0! = 1
You are given 4 zeros. Can you get a value of 24. You can use the operator as many times as you want.