Showing posts with label percentage. Show all posts
Showing posts with label percentage. Show all posts

Friday, July 24, 2015

problems on percentage

Q as a percentage of P is equal to P as a percentage of (P + Q). Find Q as a percentage of P.

A. 62%
B. 50%
C. 75%
D. 66%

Thursday, July 23, 2015

percentage

Two students appear in an examination. One of them secured 9 marks more than the  
other and his marks was 56% of the sum of their marks. What are the marks obtained by them?   
      
A. 42, 33
B. 42, 36          C. 44, 33           D. 44, 36


Problems on Percentage STD VII

A student has to obtain 33% of the total marks to pass. He has got 125 marks and has failed by 40 marks. The maximum marks for the exam are:

A. 600           B. 500             C. 400           D. 300

Wednesday, September 3, 2014

percentage

Refer to the path followed by the ball in the diagram below. every time the ball hits the ground it looses 20% of its energy. what is the energy left in the ball just after it hits the ground for the third time.











Monday, October 21, 2013

percentage



       A person split his property amongst his three sons. The youngest one got 50% of the entire property, the second got $10,000. The eldest got 20% less than the youngest. How much did the eldest son get?

Sunday, August 4, 2013

percentage



The inflation in the economy is @ 9% per annum. A company decides to revise the salary of all its employees by 5%. By how much should the consumption by individuals come down so as to beat the inflation?

percentage




A farmer stores 10000 kg of potatoes in an underground cellar. At the prevailing buying rates in the whole sale market he is unable to make any profit. He is advised that the market price of potatoes will climb @ 3% per month, whereas the loss in weight of potatoes due to evaporation of water was @1% per month.
After how many months should he sell his stock of potatoes so as to make a profit of 10%.


 

 Check the answer:
 

Monday, July 22, 2013

magic box method for solving problems on percentage STD VII



Are problems on “percentage” a cause of concern for you? You may wish to try out this magic box. It may take away your trouble?

I will illustrate the concept with an example;



Say, Nanu sells a pen at a profit of 20%.

It means if Nanu were to buy the pen at Rs 100, then the selling price will be Rs 120.

Say, vegetable prices have gone up by 15%.

It means that vegetables which were earlier costing Rs 100, can now be purchased for Rs 115.

Rain fall in 2013 was 30% above average in Mumbai.

It means that if the average rainfall in Mumbai is 100 mm, then in the year 2013 the rainfall is 130 mm.

Lata’s has scored 10% more than Suresh in the Maths exam.

It means if Suresh has secured 100 in maths, then Lata has got 110.



Similarly,

Say, Nanu sells a pen at a loss of 20%.

It means if Nanu were to buy the pen at Rs 100, then the selling price will be Rs 80.

Say, vegetable prices have gone down by 15%.

It means that vegetables which were earlier costing Rs 100, can now be purchased for Rs 85.

Rain fall in 2013 was 30% below average in Mumbai.

It means that if the average rainfall in Mumbai is 100 mm, then in the year 2013 the rainfall is 70mm.

Lata’s has scored 10% less than Suresh in the Maths exam.

It means if Suresh has secured 100 in maths, then Lata has got 90.



If this concept has got ingrained in you, then we will move to the next step.

Cost of cabbage was $ 2 per kg last week. This week the prices have gone up by 14%. What is the per kg cost of cabbage this week?

Let us construct our magic box:


Last week
This week
Cabbage cost  based on %
100
114
Actual cabbage cost
$ 2
?  (say, x)



Now, note this step carefully,

 Ratio in the first row = ratio in the second row.

So, 100/ 114 = 2/x

You could also write

114/100 = x/2, and you will still not make a mistake.

So, if 100/ 114 = 2/x

Or, 100x = 2 x 114

Or, x = 2 x 114/100 = 2.28

The present cabbage cost is $ 2.28.

General rule:




Event 1
Event 2
Comparison based on %
100
A1
actual
B1
C1



Rule:

 A1/100 = C1/B1,

You could also write 100/A1 = B1/C1.

Then solve for the missing entity.



Let us take another example:

The rainfall in Mumbai for the year 2013 is 30% more than the average rainfall of Mumbai. The average rain fall is 250mm.What is the rainfall in 2013.


Average
2013
Rainfall based on %
100
130
Actual
250
? let us say, x

     



Now, write, 

100/130 = 250/x

Or, x = 250 x 130 / 100 =  325 mm



We will take it forward in the next lesson.