simple equation

Simple Equation

Simple Equation

Simple Equations

Simple Equations

Simple Equation

tougher problems in simple equation

A car did a journey in "t" hours. If the average speed had been "m" km/hr greater, the journey would have taken "y" hours less. What was the length of the journey?

tougher problems on simple equations

A fraction is such that if "c" is added to the numerator and "d" to the denominator, the value of the fraction becomes 1/x. If the numerator of the original fraction is doubled and the denominator is increased by "e", the fraction becomes 1/y. Find the original fraction.

tougher questions on simple equation

A man rides one third of the distance from A to B at the rate of "a" km/hr and the remainder at "2b" km/hr. if he had traveled at the uniform rate of "3c" km/hr, he could have ridden from A to B and back again in the same time.
Prove that 2/c = (1/a) + (1/b)

tougher problems on simple equation

There are two mixtures of  acid and water, one of which contains twice as much water as acid, and  the other three times as much acid as water. How much must be taken from each in order to fill a liter measure, in which the water and the acid shall be equally mixed?

Simple Equation

A man bicycles half the distance from  one town to the another at 24 km/hr, and the other half at 16 km/hr. A second man bicycles all the way at 22.5 km/hr. If the difference in the time taken is 5 1/2 min, then what is the whole distance?

framing of equation

A man buys oranges at the rate of "p" for a $, and by selling them at "q" cents a dozen makes a profit of  "r" %. 

Show that pq -12r = 1200


Answer:
Cost of 12 oranges = 12/p
Selling price of 12 oranges = q/100
Gain = q/100 - 12/p = (pq - 1200)/100p
Gain % = r = 100 [(pq - 1200)/100p] / 12/p
or, 12r = 100p [(pq - 1200)/100p]
or, 12r = pq - 1200
or, pq - 12r = 1200

mixtures, STD V

A, B and C have $ 507 between them. B and C together have $ 345 and C and A together have $ 305. How much does C have?

Answer:

A+B+C =507--------(1)

B+C = 345----------(2)

A+C = 305----------(3)

Adding (2) and (3), we get A+2B+C = 345 + 305------(4)

Substituting (1) in (4), we get

507 + B = 650

Or, B = 143

Therefore, C = 345 – 143 = 202

A Sum of money is divided into A, B and C. C gets twice as much as A, A and B together get $70, and B and C together get $90. How much does each person get?

Answer:

2A = C -------(1)

A + B = 70------(2)

B +C = 90-------(3)

(2) – (3)

A – C = -20,-----(4)

Substituting (1) in (4), we get

A – 2A = -20

Or, A = 20, therefore B = 50 and C = 40