Saturday, July 20, 2013

tougher problems in simple equation

A car did a journey in "t" hours. If the average speed had been "m" km/hr greater, the journey would have taken "y" hours less. What was the length of the journey?







Answer:

Let the length of the journey be x.

therefore speed of the journey = x/t

Also given x = [(x/t)+ m](t - y)

or, xt = (x + tm) (t - y)

or, xt = xt - xy + t2m - tmy

or, xy = tm( t - y)

or, x = tm(t - y)/ y

1 comment :

  1. Maths has been a tough nut to crack, with the help of the Sample Papers on the topic is very helpful. Thanks for your efforts, Sir. Please keep on posting with latest questions and answers.

    ReplyDelete