Find the value of M and N respectively if M39048458N is divisible by 8 and 11, where M and N are single digit integers?
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Showing posts with label Division. Show all posts
Showing posts with label Division. Show all posts
Friday, September 26, 2014
Thursday, September 25, 2014
Tuesday, September 23, 2014
division
A number when divided by a divisor leaves a remainder of 24. When twice the original number is divided by the same divisor, the remainder is 11. What is the value of the divisor?
Saturday, August 16, 2014
division and numbers
If the number 5a8b7c is completely divisible by 66 and if b
+ c = 11 and a + b = 14, then find the value of (a – b).
47th question of MAT 2014 STD V and STD VI
Answer:
The sum of the numbers = 5 + 8 + 7 + a + b + c = 20 + a + b
+ c ------------------------- (1)
Substituting (a + b) = 14 in equation 1 we get
The sum of the numbers = 20 + 14 + c = 34 + c
Now since the number is completely divisible by 66, it must
be divisible by 2, 3 and 11.
If the number is divisible by 2 then “c” has to be an even
number or 0.
Also, since the number is divisible by 3, hence sum of
numbers must be divisible by 3
c
|
Sum of the numbers = 34 + c
|
Selection
|
0
|
34
|
3 + 4 = 7 => not divisible by 3
|
2
|
36
|
3 + 6 = 9 => divisible
by 3
|
4
|
38
|
3 + 8 = 11 => not divisible by 3
|
6
|
40
|
4 + 0 = 4 => not divisible by 3
|
8
|
42
|
4 + 2 = 6 => divisible
by 3
|
Therefore, c can have only 2 possible values of 2 and 8 to
satisfy the divisibility test of 2 and 3.
Now we have to check the divisibility test of 11.
i.e. the sum of the numbers in the even place – the sum of
the numbers in the odd place should be a multiple of 11.
Now, sum of the numbers in the even place = 7 + 8 + 5 = 20
Sum of the numbers in the odd place = a + b + c = 14 + c
c
|
Sum of the numbers in even place
- sum of number in odd place
= absolute { 20 – (14 + c) }
|
Selection
|
2
|
4
|
=> not multiple of 11
|
8
|
2
|
=> not multiple of 11
|
So, I think no answer is possible with the given set of
conditions.
Thursday, August 14, 2014
Monday, August 4, 2014
JMO STD V and STD VI - divisibility
What is the unit digit in (6324)1797 × (615)316 × (341)476
JMO STD V and STD VI
JMO --- Divisibility test
When (6363 +63) is divided by 64, the remainder is........................
for JMO STD VII and STD VIII
Saturday, August 2, 2014
JMO -- DIvisibility
Which are the two numbers less than 260 that exactly divides
232 – 1?
JMO – VII and VIII
Tuesday, September 17, 2013
Sunday, September 8, 2013
Saturday, August 24, 2013
Tuesday, August 20, 2013
Friday, August 9, 2013
number, divisibility
Show that the square of any positive integer cannot be of the
form 5q + 2 or 5q + 3 for any integer q
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