What is the remainder when 9 1 + 9 2 + 9 3 + . . . . + 9 8 is divided by 6?
answer:
answer:
= 9 x (1 +9 + 92
....................+ 97)/ 6
= 3 x (1 + 9 + 1 + 9 + 1 +
9 + 1 + 9)/2 ...... recording the units
place only
= 3 x ..0 / 2 ...... recording
the units place only
= since the units place is
zero, there is no remainder.
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