Three pipes A, B and C can fill up a tank from empty to full in 10 minutes, 20 minutes, and 30 minutes respectively. When the tank is empty, all the three pipes are opened. A, B and C discharge chemical solutions P,Q and R respectively. What is the proportion of the solution P in the liquid in the tank after 6 minutes?
Answer:
proportion of P after 6 mins = 6 x 1/10 = 6/10
Proportion of liquid P,Q and R in the tank = 6 x ( 1/10 + 1/20 + 1/30) = 6 x 11/60 = 11/10
So, proportion of P in tank after 6 mins = (6/10)/(11/10) = 6/11
Answer:
proportion of P after 6 mins = 6 x 1/10 = 6/10
Proportion of liquid P,Q and R in the tank = 6 x ( 1/10 + 1/20 + 1/30) = 6 x 11/60 = 11/10
So, proportion of P in tank after 6 mins = (6/10)/(11/10) = 6/11
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