Sunday, February 23, 2014

JMO STD V and VI

 




 Answer:

Given:
                      a        b      0
                      b        a      0
                +              a      b
                                b      a


x = 100 (a + b) + 2 (a + b) x 10 + (a + b)

or, (a + b) x (100 + 20 + 1)
or, (a + b) x 121

which is divisible by 11.

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